Page 43 - Rekayasa Pantai
P. 43
T 1 sin 2 . t sin 2 t
= − + dt
O 2 k 2 k 2
LT
= (3.20)
2
sin 2 (kx − t ) dtdx. = 1 ( 1− cos ( 2 kx − t ) dtdx.
2
1 T sin 2 (kx − ) t L
= x − dt
2 O k 2 O
LT
= (3.21)
2
LT
1 a 2 w 2 h sinh 2 kh
E =
k
2 sinh 2 kh 2 2 h k
2 2 sinh khcosh kh
= a 2 LT
8 sinh 2 kh k
fg 2
= a 2 LT
8 gk tanh kh
= H 2 LT (3.22)
16
Kerapatan Energi :
1 H 2
E = H 2 LT = (3.23)
k
LT 16 16
Energi Potensial :
L T 1
E p = 2 dx. dt
O O 2
31